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	<title>Comments on: How do I translate this word problem to a workable equation?</title>
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	<link>http://op-snj.org/translate/how-do-i-translate-this-word-problem-to-a-workable-equation</link>
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		<title>By: Kat K</title>
		<link>http://op-snj.org/translate/how-do-i-translate-this-word-problem-to-a-workable-equation/comment-page-1#comment-4</link>
		<dc:creator>Kat K</dc:creator>
		<pubDate>Sat, 01 Aug 2009 09:34:59 +0000</pubDate>
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		<description>x - y = 16  and  3(x) = 7(y)

&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>x &#8211; y = 16  and  3(x) = 7(y)</p>
<p><b>References : </b></p>
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		<title>By: Baganagalagachoogaboogaloogayay!</title>
		<link>http://op-snj.org/translate/how-do-i-translate-this-word-problem-to-a-workable-equation/comment-page-1#comment-3</link>
		<dc:creator>Baganagalagachoogaboogaloogayay!</dc:creator>
		<pubDate>Sat, 01 Aug 2009 08:58:59 +0000</pubDate>
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		<description>Let&#039;s first figure out what we don&#039;t know, and make those variables.
We need to find 2 numbers that follow those two rules.
Let&#039;s call those 2 numbers x and y.

So the difference between the two numbers is 16.
x - y = 16

Three times the larger number (x) is 7 times the smaller (y).
So, 3 times the larger number is 3 * x = 3x
7 times the smaller = 7 * y = 7y
3x = 7y

One way to solve a linear equation is called &quot;substitution&quot;, when you find x = something not related to x, and then plug that into the equation.

So since 3x = 7y,
x = 7y/3

Plug that into x - y = 16

7y/3 - y = 16

Since y = 3y/3 (the threes cancel)

7y/3 - 3y/3 = 16

See the common denominators? Let&#039;s simplify.

4y/3 = 16

Let&#039;s divide both sides by 4

y/3 = 4

Multiply both sides of the equation by 3

y = 12

Now plug again into the equation for y and solve for x

x - y = 16
x - 12 = 16
x = 28

The two numbers are 12 and 28.

Hope this helped!&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>Let&#8217;s first figure out what we don&#8217;t know, and make those variables.<br />
We need to find 2 numbers that follow those two rules.<br />
Let&#8217;s call those 2 numbers x and y.</p>
<p>So the difference between the two numbers is 16.<br />
x &#8211; y = 16</p>
<p>Three times the larger number (x) is 7 times the smaller (y).<br />
So, 3 times the larger number is 3 * x = 3x<br />
7 times the smaller = 7 * y = 7y<br />
3x = 7y</p>
<p>One way to solve a linear equation is called &quot;substitution&quot;, when you find x = something not related to x, and then plug that into the equation.</p>
<p>So since 3x = 7y,<br />
x = 7y/3</p>
<p>Plug that into x &#8211; y = 16</p>
<p>7y/3 &#8211; y = 16</p>
<p>Since y = 3y/3 (the threes cancel)</p>
<p>7y/3 &#8211; 3y/3 = 16</p>
<p>See the common denominators? Let&#8217;s simplify.</p>
<p>4y/3 = 16</p>
<p>Let&#8217;s divide both sides by 4</p>
<p>y/3 = 4</p>
<p>Multiply both sides of the equation by 3</p>
<p>y = 12</p>
<p>Now plug again into the equation for y and solve for x</p>
<p>x &#8211; y = 16<br />
x &#8211; 12 = 16<br />
x = 28</p>
<p>The two numbers are 12 and 28.</p>
<p>Hope this helped!<br /><b>References : </b></p>
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